-[7z-(10z+4)]=4+(2z+0)

Solution for -[7z-(10z+4)]=4+(2z+0) equation:

Simplifying
-1[7z + -1(10z + 4)] = 4 + (2z + 0)

Reorder the terms:
-1[7z + -1(4 + 10z)] = 4 + (2z + 0)
-1[7z + (4 * -1 + 10z * -1)] = 4 + (2z + 0)
-1[7z + (-4 + -10z)] = 4 + (2z + 0)

Reorder the terms:
-1[-4 + 7z + -10z] = 4 + (2z + 0)

Combine like terms: 7z + -10z = -3z
-1[-4 + -3z] = 4 + (2z + 0)
[-4 * -1 + -3z * -1] = 4 + (2z + 0)
[4 + 3z] = 4 + (2z + 0)

Reorder the terms:
4 + 3z = 4 + (0 + 2z)
Remove the zero:
4 + 3z = 4 + (2z)
4 + 3z = 4 + (2z)

Add '-4' to each side of the equation.
4 + -4 + 3z = 4 + -4 + (2z)

Combine like terms: 4 + -4 = 0
0 + 3z = 4 + -4 + (2z)
3z = 4 + -4 + (2z)

Combine like terms: 4 + -4 = 0
3z = 0 + (2z)
3z = (2z)

Solving
3z = (2z)

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '(-2z)' to each side of the equation.
3z + (-2z) = (2z) + (-2z)

Combine like terms: 3z + (-2z) = 1z
1z = (2z) + (-2z)

Combine like terms: (2z) + (-2z) = 0
1z = 0

Divide each side by '1'.
z = 0

Simplifying
z = 0